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Given an integer array nums
and two integers firstLen
and secondLen
, return the maximum sum of elements in two non-overlapping subarrays with lengths firstLen
and secondLen
.
The array with length firstLen
could occur before or after the array with length secondLen
, but they have to be non-overlapping.
A subarray is a contiguous part of an array.
Example 1:
Input: nums = [0,6,5,2,2,5,1,9,4], firstLen = 1, secondLen = 2
Output: 20
Explanation: One choice of subarrays is [9] with length 1, and [6,5] with length 2.
Example 2:
Input: nums = [3,8,1,3,2,1,8,9,0], firstLen = 3, secondLen = 2
Output: 29
Explanation: One choice of subarrays is [3,8,1] with length 3, and [8,9] with length 2.
Example 3:
Input: nums = [2,1,5,6,0,9,5,0,3,8], firstLen = 4, secondLen = 3
Output: 31
Explanation: One choice of subarrays is [5,6,0,9] with length 4, and [3,8] with length 3.
Constraints:
1 <= firstLen, secondLen <= 1000
2 <= firstLen + secondLen <= 1000
firstLen + secondLen <= nums.length <= 1000
0 <= nums[i] <= 1000
[Array]
[Dynamic Programming]
[Sliding Window]
Hints
Hint 1
We can use prefix sums to calculate any subarray sum quickly.
For each L length subarray, find the best possible M length subarray that occurs before and after it.